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-16x^2+41.6x=4
We move all terms to the left:
-16x^2+41.6x-(4)=0
a = -16; b = 41.6; c = -4;
Δ = b2-4ac
Δ = 41.62-4·(-16)·(-4)
Δ = 1474.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41.6)-\sqrt{1474.56}}{2*-16}=\frac{-41.6-\sqrt{1474.56}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41.6)+\sqrt{1474.56}}{2*-16}=\frac{-41.6+\sqrt{1474.56}}{-32} $
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